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How Liquid LSD is Dosed
The manufacturer of liquid LSD will determine the potency of each drop, by controlling the ratio of crystalline LSD to the alcohol/water solvent used. For example, if a manufacturer wants a 125 ug dose from a single drop and one assumes a standard dropper bottle dispenses 0.05 ml per drop of LSD (this is a commonly used assumption), then one must mix a concentration of 125 ug of LSD per 0.05 ml of final solution.
If preparing 10,000 drops, one would need 1,250,000 ug of LSD (125 ug x 10,000 units = 1,250,000 ug, or 1.25 grams). One would also need enough solvent to produce 500 ml of final liquid. In this final solution, each 0.05 ml drop of solution contains 125 ug of LSD. (As an aside, the density of LSD is 1.2±0.1 g cm−31.2±0.1 g cm−3, and therefore 1.25 grams of LSD is around 58 ml. So one would use 442 ml of solvent for 1.25 g of LSD to produce 500 ml of LSD solution).
The key fact is that a single 0.05 ml drop of solution from a dropper bottle consists of a specified amount of LSD and the rest is an inactive solvent. The strength of the LSD dose can be changed by increasing the ratio of LSD to solvent in the solution.
To get a desired dose, two conditions must be true: (i) the LSD solution is at the desired concentration (e.g., 125 ug per 0.05 ml), and (ii) the dispensing device consistently distributes the desired amount of liquid (e.g., 0.05 ml per drop).